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D) Friction - force between 2 surfaces that oppose motion

Depends only on:

1) texture of each surface

What do plows have on their wheels to increase friction?

2) force holding objects together

What do race cars have mounted on their
rear hood to increase their friction?

Spoilers increase force between tire and road

Why do some people put barbells
in their car trunk on a snowy day? 

Weights in a car truck
increase the tires force on the road

Two kinds of friction

(f_s) 1) Static Friction - force of friction that must be overcome to move an object at rest.

(f_k) 2) Kinetic Friction - force of friction that opposes a moving object.

Kinetic friction is weaker than static friction

f_k<f_s

Friction Equations

Static friction: f_s= u_sF_n    

Kinetic friction: f_k = u_kF_n

f_s = force of static friction
f_k = force of kinetic friction

F_n = normal force (The supporting force)

u_s = coefficient of static friction - "the roughness number"

u_k = coefficient of kinetic friction - "the roughness number"

1. Relates to texture of surfaces in contact

2. Calculated in lab

ice and skate - low uk

What do skiers do to their skis to improve the coefficient of friction between their skis and the snow?

FRICTION force vector always drawn opposite to motion.

*** At constant velocity:

 F applied =  friction force

a = 0

Fnet = 0

*** When object is moving on a horizontal surface:
 

F_n = weight force = w = mg

On a horizontal surface:

f_s= F_nu_s = wU_s = mgU_s

f_k= F_nU_k = wU_k = mgU_k

Ex 1) If an object is moving on a horizontal surface and you doubled the weight force on the object, how would that change the kinetic friction force?

(Hint: weight force = normal force on horizontal surface.)

kinetic friction would double 

On a horizontal surface

Static Friction equation

f_s= F_nu_s = wu_s = mgu_s

Kinetic friction equation

f_k= F_nU_k = wU_k = mgU_k

 1) What would happen to the kinetic friction (f_k) if:

a) U_k (the roughness number) were halved?

f_k= F_nU_k

f_k  would be halved

b) tripled the weight force (F)?

f_k= wU_k

f_k  would be tripled

c) you turned the block on its' side?

f_k= F_nU_k = wU_k = mgU_k

f_k  would be  unchanged

Friction Questions