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PE and k
e) PEs in terms of k
1. P.E.s = Fx
Average Force: F = F/2
2. PE = (F/2)x
substitute F = Kx (On reference)
3. P.E.s = (1/2)(Kx)x
(On reference)
Ex 1) A force of 12. N stretches a spring and makes it .15m longer a) What's the spring constant (k) of this spring?
k = F/x
= 12. N/.15 m
= 80. N/m
b) P.E. of this spring?
PEs = (½)Kx2
= 1/2(80. N/m)(.15 m)2
PEs = .90 Joules
Ex) If 15. joules of energy are stored in the stretched spring, what is the value of the spring constant
Ex) If 15. joules of energy are stored in the stretched spring, what is the value of the spring constant
15. J = (½)K(.50 m)2
15. J = .50 k(.25)
= 120 N/m
P.E.s = 1/2(kx2)
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